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Scheduling based problem
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar ManaraDeducing Two Numbers based on their Difference and RatioThe 2 million, er, 20 dollar problemAdd a number to each vertex of a triangle such that each edge adds to a perfect squareHexagonal sum fillingEight distinct numbers in the tableIncreasing rows and columnsA simple grid puzzle123456789=1 problemFilling a chessboard with -1, 0 and 1Input/Output Problem #7
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
add a comment |
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
add a comment |
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
mathematics packing
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 2 hours ago
JonMark PerryJonMark Perry
20.9k64199
20.9k64199
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 2 hours ago
BassBass
31.5k474192
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 2 hours ago
NarloreNarlore
34615
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 2 hours ago
BassBass
31.5k474192
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
add a comment |
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 2 hours ago
BassBass
31.5k474192
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
add a comment |
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 2 hours ago
BassBass
31.5k474192
$endgroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 2 hours ago
BassBass
31.5k474192
edited 1 min ago
answered 2 hours ago
BassBass
31.5k474192
answered 2 hours ago
BassBass
31.5k474192
answered 2 hours ago
BassBass
31.5k474192
31.5k474192
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
add a comment |
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
2 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
1 hour ago
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 2 hours ago
NarloreNarlore
34615
$endgroup$
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 2 hours ago
NarloreNarlore
34615
$endgroup$
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 2 hours ago
NarloreNarlore
34615
$endgroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 2 hours ago
NarloreNarlore
34615
edited 2 hours ago
answered 2 hours ago
NarloreNarlore
34615
answered 2 hours ago
NarloreNarlore
34615
answered 2 hours ago
NarloreNarlore
34615
34615
add a comment |
add a comment |
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