How can I print the prosodic symbols in LaTeX?What is accents commands behavior ?Can I get a widebar without...
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How can I print the prosodic symbols in LaTeX?
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The package "metre" or "metrix" is very good to print the prosodic accent for LaTeX. But, I counldn't print several signs. Does anyone know how to print this one ?

symbols accents poetry font-metrics
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The package "metre" or "metrix" is very good to print the prosodic accent for LaTeX. But, I counldn't print several signs. Does anyone know how to print this one ?

symbols accents poetry font-metrics
New contributor
user187632 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Erm... which one?
– campa
2 hours ago
add a comment |
The package "metre" or "metrix" is very good to print the prosodic accent for LaTeX. But, I counldn't print several signs. Does anyone know how to print this one ?

symbols accents poetry font-metrics
New contributor
user187632 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
The package "metre" or "metrix" is very good to print the prosodic accent for LaTeX. But, I counldn't print several signs. Does anyone know how to print this one ?

symbols accents poetry font-metrics
symbols accents poetry font-metrics
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user187632 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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asked 2 hours ago
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1
Erm... which one?
– campa
2 hours ago
add a comment |
1
Erm... which one?
– campa
2 hours ago
1
1
Erm... which one?
– campa
2 hours ago
Erm... which one?
– campa
2 hours ago
add a comment |
1 Answer
1
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I don't know a prosodic from prozac, but if you are talking about those overlines...
Note: I made them of fixed width, centered over the argument. If you want them of variable width, extending the full argument, I can make changes.
documentclass{article}
usepackage{amsmath,stackengine}
newcommandprosodic[1]{%
ifx1#1expandafterprosodiconeelse
ifx2#1expandafterexpandafterexpandafterprosodictwoelse
ifx3#1expandafterexpandafterexpandafterexpandafter
expandafterexpandafterexpandafterprosodicthreeelse
fififi
}
newcommandprosodicone[1]{stackengine{0pt}{#1}{$overline{%
makebox[.8em]{vphantom{#1}}}$}{O}{c}{F}{T}{L}}
newcommandprosodictwo[1]{stackengine{0pt}{#1}{$overline{overline{%
makebox[.8em]{vphantom{#1}}}}$}{O}{c}{F}{T}{L}}
newcommandprosodicthree[1]{stackengine{0pt}{#1}{$overline{overline{%
overline{makebox[.8em]{vphantom{#1}}}}}$}{O}{c}{F}{T}{L}}
begin{document}
devprosodic1{in}t
devprosodic2{in}t
devprosodic3{in}t
mon
ennuprosodic3{i}!
end{document}

One last point of style. The overline is done relative to the argument height, so that the prosodic1{x} accent will be lower than prosodic1{i}. If the convention is for the height of the initial prosodic accent to be fixed, regardless of the letter, then one could simply change all three instances of vphantom{#1} to vphantom{X}.
add a comment |
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1 Answer
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I don't know a prosodic from prozac, but if you are talking about those overlines...
Note: I made them of fixed width, centered over the argument. If you want them of variable width, extending the full argument, I can make changes.
documentclass{article}
usepackage{amsmath,stackengine}
newcommandprosodic[1]{%
ifx1#1expandafterprosodiconeelse
ifx2#1expandafterexpandafterexpandafterprosodictwoelse
ifx3#1expandafterexpandafterexpandafterexpandafter
expandafterexpandafterexpandafterprosodicthreeelse
fififi
}
newcommandprosodicone[1]{stackengine{0pt}{#1}{$overline{%
makebox[.8em]{vphantom{#1}}}$}{O}{c}{F}{T}{L}}
newcommandprosodictwo[1]{stackengine{0pt}{#1}{$overline{overline{%
makebox[.8em]{vphantom{#1}}}}$}{O}{c}{F}{T}{L}}
newcommandprosodicthree[1]{stackengine{0pt}{#1}{$overline{overline{%
overline{makebox[.8em]{vphantom{#1}}}}}$}{O}{c}{F}{T}{L}}
begin{document}
devprosodic1{in}t
devprosodic2{in}t
devprosodic3{in}t
mon
ennuprosodic3{i}!
end{document}

One last point of style. The overline is done relative to the argument height, so that the prosodic1{x} accent will be lower than prosodic1{i}. If the convention is for the height of the initial prosodic accent to be fixed, regardless of the letter, then one could simply change all three instances of vphantom{#1} to vphantom{X}.
add a comment |
I don't know a prosodic from prozac, but if you are talking about those overlines...
Note: I made them of fixed width, centered over the argument. If you want them of variable width, extending the full argument, I can make changes.
documentclass{article}
usepackage{amsmath,stackengine}
newcommandprosodic[1]{%
ifx1#1expandafterprosodiconeelse
ifx2#1expandafterexpandafterexpandafterprosodictwoelse
ifx3#1expandafterexpandafterexpandafterexpandafter
expandafterexpandafterexpandafterprosodicthreeelse
fififi
}
newcommandprosodicone[1]{stackengine{0pt}{#1}{$overline{%
makebox[.8em]{vphantom{#1}}}$}{O}{c}{F}{T}{L}}
newcommandprosodictwo[1]{stackengine{0pt}{#1}{$overline{overline{%
makebox[.8em]{vphantom{#1}}}}$}{O}{c}{F}{T}{L}}
newcommandprosodicthree[1]{stackengine{0pt}{#1}{$overline{overline{%
overline{makebox[.8em]{vphantom{#1}}}}}$}{O}{c}{F}{T}{L}}
begin{document}
devprosodic1{in}t
devprosodic2{in}t
devprosodic3{in}t
mon
ennuprosodic3{i}!
end{document}

One last point of style. The overline is done relative to the argument height, so that the prosodic1{x} accent will be lower than prosodic1{i}. If the convention is for the height of the initial prosodic accent to be fixed, regardless of the letter, then one could simply change all three instances of vphantom{#1} to vphantom{X}.
add a comment |
I don't know a prosodic from prozac, but if you are talking about those overlines...
Note: I made them of fixed width, centered over the argument. If you want them of variable width, extending the full argument, I can make changes.
documentclass{article}
usepackage{amsmath,stackengine}
newcommandprosodic[1]{%
ifx1#1expandafterprosodiconeelse
ifx2#1expandafterexpandafterexpandafterprosodictwoelse
ifx3#1expandafterexpandafterexpandafterexpandafter
expandafterexpandafterexpandafterprosodicthreeelse
fififi
}
newcommandprosodicone[1]{stackengine{0pt}{#1}{$overline{%
makebox[.8em]{vphantom{#1}}}$}{O}{c}{F}{T}{L}}
newcommandprosodictwo[1]{stackengine{0pt}{#1}{$overline{overline{%
makebox[.8em]{vphantom{#1}}}}$}{O}{c}{F}{T}{L}}
newcommandprosodicthree[1]{stackengine{0pt}{#1}{$overline{overline{%
overline{makebox[.8em]{vphantom{#1}}}}}$}{O}{c}{F}{T}{L}}
begin{document}
devprosodic1{in}t
devprosodic2{in}t
devprosodic3{in}t
mon
ennuprosodic3{i}!
end{document}

One last point of style. The overline is done relative to the argument height, so that the prosodic1{x} accent will be lower than prosodic1{i}. If the convention is for the height of the initial prosodic accent to be fixed, regardless of the letter, then one could simply change all three instances of vphantom{#1} to vphantom{X}.
I don't know a prosodic from prozac, but if you are talking about those overlines...
Note: I made them of fixed width, centered over the argument. If you want them of variable width, extending the full argument, I can make changes.
documentclass{article}
usepackage{amsmath,stackengine}
newcommandprosodic[1]{%
ifx1#1expandafterprosodiconeelse
ifx2#1expandafterexpandafterexpandafterprosodictwoelse
ifx3#1expandafterexpandafterexpandafterexpandafter
expandafterexpandafterexpandafterprosodicthreeelse
fififi
}
newcommandprosodicone[1]{stackengine{0pt}{#1}{$overline{%
makebox[.8em]{vphantom{#1}}}$}{O}{c}{F}{T}{L}}
newcommandprosodictwo[1]{stackengine{0pt}{#1}{$overline{overline{%
makebox[.8em]{vphantom{#1}}}}$}{O}{c}{F}{T}{L}}
newcommandprosodicthree[1]{stackengine{0pt}{#1}{$overline{overline{%
overline{makebox[.8em]{vphantom{#1}}}}}$}{O}{c}{F}{T}{L}}
begin{document}
devprosodic1{in}t
devprosodic2{in}t
devprosodic3{in}t
mon
ennuprosodic3{i}!
end{document}

One last point of style. The overline is done relative to the argument height, so that the prosodic1{x} accent will be lower than prosodic1{i}. If the convention is for the height of the initial prosodic accent to be fixed, regardless of the letter, then one could simply change all three instances of vphantom{#1} to vphantom{X}.
edited 1 hour ago
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
163k9208421
163k9208421
add a comment |
add a comment |
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1
Erm... which one?
– campa
2 hours ago