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/bin/ls sorts differently than just ls

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}

3

$ ls |sort

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm

xyz-0.0.1-1554323568.rpm



$ /bin/ls |sort

xyz-0.0.1-1554323568.rpm

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm



$ which ls

alias ls='/bin/ls --color'

        /bin/ls

Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?

linux command-line bash unix

share|improve this question

asked 1 hour ago

Josh M.Josh M.

65951227

add a comment | 

3

$ ls |sort

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm

xyz-0.0.1-1554323568.rpm



$ /bin/ls |sort

xyz-0.0.1-1554323568.rpm

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm



$ which ls

alias ls='/bin/ls --color'

        /bin/ls

Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?

linux command-line bash unix

share|improve this question

asked 1 hour ago

Josh M.Josh M.

65951227

add a comment | 

$ ls |sort

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm

xyz-0.0.1-1554323568.rpm



$ /bin/ls |sort

xyz-0.0.1-1554323568.rpm

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm



$ which ls

alias ls='/bin/ls --color'

        /bin/ls

Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?

linux command-line bash unix

share|improve this question

asked 1 hour ago

Josh M.Josh M.

65951227

$ ls |sort

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm

xyz-0.0.1-1554323568.rpm



$ /bin/ls |sort

xyz-0.0.1-1554323568.rpm

xyz-0.0.1-1554490900.rpm

xyz-0.0.1-1554745305.rpm

xyz-0.0.1-1554751021.rpm

xyz-0.0.1-1555513460.rpm

xyz-0.0.1-1555951745.rpm



$ which ls

alias ls='/bin/ls --color'

        /bin/ls

share|improve this question

asked 1 hour ago

Josh M.Josh M.

65951227

share|improve this question

asked 1 hour ago

Josh M.Josh M.

65951227

asked 1 hour ago

Josh M.Josh M.

65951227

asked 1 hour ago

Josh M.Josh M.

65951227

2 Answers
2

active

oldest

votes

6

Do:

/bin/ls --color > file1

/bin/ls > file2

and compare content, you'll see the difference.

Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).

share|improve this answer

answered 1 hour ago

TomekTomek

44935

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I assume this is just a "known thing" and people understand ls + sorting should be done directly via /bin/ls vs. ls.
  
  – Josh M.
  52 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.
  
  – Kamil Maciorowski
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.
  
  – John1024
  40 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.
  
  – Freddy
  28 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.
  
  – John1024
  27 mins ago
  

  
  
  
  

add a comment | 

1

In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
of the non-colored output. The other lines are sorted equally.

If we have at a look at the colored escape codes (non-sorted), we can see that the first
line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).

$ /bin/ls --color xyz* | cat -A

^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$

share|improve this answer

answered 37 mins ago

FreddyFreddy

3035

add a comment | 

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6

Do:

/bin/ls --color > file1

/bin/ls > file2

and compare content, you'll see the difference.

Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).

share|improve this answer

answered 1 hour ago

TomekTomek

44935

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I assume this is just a "known thing" and people understand ls + sorting should be done directly via /bin/ls vs. ls.
  
  – Josh M.
  52 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.
  
  – Kamil Maciorowski
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.
  
  – John1024
  40 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.
  
  – Freddy
  28 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.
  
  – John1024
  27 mins ago
  

  
  
  
  

add a comment | 

6

Do:

/bin/ls --color > file1

/bin/ls > file2

and compare content, you'll see the difference.

Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).

share|improve this answer

answered 1 hour ago

TomekTomek

44935

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I assume this is just a "known thing" and people understand ls + sorting should be done directly via /bin/ls vs. ls.
  
  – Josh M.
  52 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.
  
  – Kamil Maciorowski
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.
  
  – John1024
  40 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.
  
  – Freddy
  28 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.
  
  – John1024
  27 mins ago
  

  
  
  
  

add a comment | 

Do:

/bin/ls --color > file1

/bin/ls > file2

and compare content, you'll see the difference.

Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).

share|improve this answer

answered 1 hour ago

TomekTomek

44935

/bin/ls --color > file1

/bin/ls > file2

share|improve this answer

answered 1 hour ago

TomekTomek

44935

answered 1 hour ago

TomekTomek

44935

answered 1 hour ago

TomekTomek

44935

1

In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
of the non-colored output. The other lines are sorted equally.

If we have at a look at the colored escape codes (non-sorted), we can see that the first
line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).

$ /bin/ls --color xyz* | cat -A

^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$

share|improve this answer

answered 37 mins ago

FreddyFreddy

3035

add a comment | 

1

In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
of the non-colored output. The other lines are sorted equally.

If we have at a look at the colored escape codes (non-sorted), we can see that the first
line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).

$ /bin/ls --color xyz* | cat -A

^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$

share|improve this answer

answered 37 mins ago

FreddyFreddy

3035

add a comment | 

In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
of the non-colored output. The other lines are sorted equally.

If we have at a look at the colored escape codes (non-sorted), we can see that the first
line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).

$ /bin/ls --color xyz* | cat -A

^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$

share|improve this answer

answered 37 mins ago

FreddyFreddy

3035

$ /bin/ls --color xyz* | cat -A

^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$

^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$

^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$

share|improve this answer

answered 37 mins ago

FreddyFreddy

3035

answered 37 mins ago

FreddyFreddy

3035

answered 37 mins ago

FreddyFreddy

3035