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How do you center multiple equations that have multiple steps?
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I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begin{center}
$N(1)=N(1+0i)$
hspace{.025cm}
$N(-1)=N(-1+0i)$
hspace{.025cm}
$N(i)=N(0+1i)$
hspace{.025cm}
$N(-i)=N(0-1i)$
end{center}
begin{center}
$N(1)=1^2+0$
hspace{.1cm}
$N(-1)=(-1)^2+0^2$
hspace{.1cm}
$N(i)=0^2+1^2$
hspace{.1cm}
$N(-i)=0^2+(-1)^2$
end{center}
begin{center}
$N(1)=1$
hspace{.5cm}
$N(-1)=1$
hspace{.5cm}
$N(i)=1$
hspace{.5cm}
$N(-i)=1$
end{center}
horizontal-alignment equations vertical-alignment
add a comment |
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begin{center}
$N(1)=N(1+0i)$
hspace{.025cm}
$N(-1)=N(-1+0i)$
hspace{.025cm}
$N(i)=N(0+1i)$
hspace{.025cm}
$N(-i)=N(0-1i)$
end{center}
begin{center}
$N(1)=1^2+0$
hspace{.1cm}
$N(-1)=(-1)^2+0^2$
hspace{.1cm}
$N(i)=0^2+1^2$
hspace{.1cm}
$N(-i)=0^2+(-1)^2$
end{center}
begin{center}
$N(1)=1$
hspace{.5cm}
$N(-1)=1$
hspace{.5cm}
$N(i)=1$
hspace{.5cm}
$N(-i)=1$
end{center}
horizontal-alignment equations vertical-alignment
Maybe use anarray
environment?
– leandriis
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago
add a comment |
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begin{center}
$N(1)=N(1+0i)$
hspace{.025cm}
$N(-1)=N(-1+0i)$
hspace{.025cm}
$N(i)=N(0+1i)$
hspace{.025cm}
$N(-i)=N(0-1i)$
end{center}
begin{center}
$N(1)=1^2+0$
hspace{.1cm}
$N(-1)=(-1)^2+0^2$
hspace{.1cm}
$N(i)=0^2+1^2$
hspace{.1cm}
$N(-i)=0^2+(-1)^2$
end{center}
begin{center}
$N(1)=1$
hspace{.5cm}
$N(-1)=1$
hspace{.5cm}
$N(i)=1$
hspace{.5cm}
$N(-i)=1$
end{center}
horizontal-alignment equations vertical-alignment
I am writing a paper that deals with Gaussian integers and I have a section where I am talking about the norm of the units in the Gaussian integers. Since there are only four units in the Gaussian integers, I'd like to have the calculations of their norms appear neatly in four columns that are centered. Basically so that you can easily look down each of the four columns and see the calculations for each unit. What I have right now sort of does that but its very sloppy and I'm sure there is a much cleaner way to do it. I'm still new to Latex so I realize this code is probably painfully inefficient but I would appreciate any suggestions of how to fix it and what packages I'd need to use to implement those changes.
begin{center}
$N(1)=N(1+0i)$
hspace{.025cm}
$N(-1)=N(-1+0i)$
hspace{.025cm}
$N(i)=N(0+1i)$
hspace{.025cm}
$N(-i)=N(0-1i)$
end{center}
begin{center}
$N(1)=1^2+0$
hspace{.1cm}
$N(-1)=(-1)^2+0^2$
hspace{.1cm}
$N(i)=0^2+1^2$
hspace{.1cm}
$N(-i)=0^2+(-1)^2$
end{center}
begin{center}
$N(1)=1$
hspace{.5cm}
$N(-1)=1$
hspace{.5cm}
$N(i)=1$
hspace{.5cm}
$N(-i)=1$
end{center}
horizontal-alignment equations vertical-alignment
horizontal-alignment equations vertical-alignment
edited 1 hour ago
Mico
289k32395783
289k32395783
asked 1 hour ago
Alex AdinolfiAlex Adinolfi
484
484
Maybe use anarray
environment?
– leandriis
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago
add a comment |
Maybe use anarray
environment?
– leandriis
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago
Maybe use an
array
environment?– leandriis
1 hour ago
Maybe use an
array
environment?– leandriis
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
Here are three different suggestions using either array
or alignedat
:
documentclass{article}
usepackage{geometry}
usepackage{amsmath}
begin{document}
[
begin{array}{llll}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
[
begin{array}{cccc}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
begin{alignat*}{4}
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
end{alignat*}
end{document}
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs
package to have toprule
and bottomrule
.
documentclass[a4paper,12pt]{article}
usepackage{array}
usepackage{booktabs}
begin{document}
[
setlengtharraycolsep{0pt}
renewcommandarraystretch{1.25}
begin{array}{r @{{}={}} l}
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
end{array}
]
end{document}
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
add a comment |
I propose this layout:
documentclass{article}
usepackage[utf8]{inputenc}%
usepackage{geometry}
usepackage[table, svgnames]{xcolor}
usepackage{mathtools}
colorlet{shadecolor}{Gainsboro!50! Lavender}
newcommand*shadebox[1]{%
colorbox{shadecolor}{hspace{1em}$displaystyle #1 $hspace{1em}}}
begin{document}
begin{equation}
begin{gathered}
begin{aligned}
N(1) & =N(1+0i)\
& =1^2+0^2
end{aligned} \[1.5ex]
shadebox{N(1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
end{aligned} \[1ex]
shadebox{N(-1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(i) & =N(0+1i) \
& =0^2+1^2
end{aligned} \[1ex]
shadebox{ N(i) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
end{aligned} \[1ex]
shadebox{N(-i) = 1}
end{gathered}
end{equation}
end{document}
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here are three different suggestions using either array
or alignedat
:
documentclass{article}
usepackage{geometry}
usepackage{amsmath}
begin{document}
[
begin{array}{llll}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
[
begin{array}{cccc}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
begin{alignat*}{4}
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
end{alignat*}
end{document}
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Here are three different suggestions using either array
or alignedat
:
documentclass{article}
usepackage{geometry}
usepackage{amsmath}
begin{document}
[
begin{array}{llll}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
[
begin{array}{cccc}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
begin{alignat*}{4}
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
end{alignat*}
end{document}
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Here are three different suggestions using either array
or alignedat
:
documentclass{article}
usepackage{geometry}
usepackage{amsmath}
begin{document}
[
begin{array}{llll}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
[
begin{array}{cccc}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
begin{alignat*}{4}
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
end{alignat*}
end{document}
Here are three different suggestions using either array
or alignedat
:
documentclass{article}
usepackage{geometry}
usepackage{amsmath}
begin{document}
[
begin{array}{llll}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
[
begin{array}{cccc}
N(1)=N(1+0i) & N(-1)=N(-1+0i) & N(i)=N(0+1i) & N(-i)=N(0-1i) \
N(1)=1^2+0 & N(-1)=(-1)^2+0^2 & N(i)=0^2+1^2 & N(-i)=0^2+(-1)^2 \
N(1)=1 & N(-1)=1 & N(i)=1 & N(-i)=1
end{array}
]
begin{alignat*}{4}
N(1)&=N(1+0i) &quad N(-1)&=N(-1+0i) &quad N(i)&=N(0+1i) &quad N(-i)&=N(0-1i) \
N(1)&=1^2+0 & N(-1)&=(-1)^2+0^2 & N(i)&=0^2+1^2 & N(-i)&=0^2+(-1)^2 \
N(1)&=1 & N(-1)&=1 & N(i)&=1 & N(-i)&=1
end{alignat*}
end{document}
answered 1 hour ago
leandriisleandriis
12.3k1833
12.3k1833
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
Thank you very much! This does exactly what I was looking to do.
– Alex Adinolfi
1 hour ago
1
1
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
@AlexAdinolfi: Glad I helped you. If you like my answer and it was helpful, please consider upvoting (by clicking on the arrows next to the score) and/or marking it as the accepted answer (by clicking on the checkmark ✓). This also applies to all your other questions to which you already recieved answers.
– leandriis
1 hour ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs
package to have toprule
and bottomrule
.
documentclass[a4paper,12pt]{article}
usepackage{array}
usepackage{booktabs}
begin{document}
[
setlengtharraycolsep{0pt}
renewcommandarraystretch{1.25}
begin{array}{r @{{}={}} l}
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
end{array}
]
end{document}
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs
package to have toprule
and bottomrule
.
documentclass[a4paper,12pt]{article}
usepackage{array}
usepackage{booktabs}
begin{document}
[
setlengtharraycolsep{0pt}
renewcommandarraystretch{1.25}
begin{array}{r @{{}={}} l}
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
end{array}
]
end{document}
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
add a comment |
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs
package to have toprule
and bottomrule
.
documentclass[a4paper,12pt]{article}
usepackage{array}
usepackage{booktabs}
begin{document}
[
setlengtharraycolsep{0pt}
renewcommandarraystretch{1.25}
begin{array}{r @{{}={}} l}
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
end{array}
]
end{document}
For example I would have used the tables in sequence (but it's just a personal taste) to give a touch of vitality.
In this case I have used the booktabs
package to have toprule
and bottomrule
.
documentclass[a4paper,12pt]{article}
usepackage{array}
usepackage{booktabs}
begin{document}
[
setlengtharraycolsep{0pt}
renewcommandarraystretch{1.25}
begin{array}{r @{{}={}} l}
toprule
N(1) &N(1+0i) \
N(-1)&N(-1+0i) \
N(i) &N(0+1i) \
N(-i)&N(1+0i) \
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1^2+0 \
N(-1)&(-1)^2+0^2\
N(i) &0^2+1^2 \
N(-i)&0^2+(-1)^2\
bottomrule
end{array}
quadRightarrowquad
begin{array}{r @{{}={}} l}
toprule
N(1) &1 \
N(-1)&1 \
N(i) &1 \
N(-i)&1 \
bottomrule
end{array}
]
end{document}
edited 24 mins ago
Mico
289k32395783
289k32395783
answered 56 mins ago
SebastianoSebastiano
11.8k42467
11.8k42467
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
add a comment |
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
@Mico Correct observation. Obviously I just wanted to give another interpretation based simply on aesthetics. If you don't need it, I'll remove it.
– Sebastiano
46 mins ago
add a comment |
I propose this layout:
documentclass{article}
usepackage[utf8]{inputenc}%
usepackage{geometry}
usepackage[table, svgnames]{xcolor}
usepackage{mathtools}
colorlet{shadecolor}{Gainsboro!50! Lavender}
newcommand*shadebox[1]{%
colorbox{shadecolor}{hspace{1em}$displaystyle #1 $hspace{1em}}}
begin{document}
begin{equation}
begin{gathered}
begin{aligned}
N(1) & =N(1+0i)\
& =1^2+0^2
end{aligned} \[1.5ex]
shadebox{N(1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
end{aligned} \[1ex]
shadebox{N(-1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(i) & =N(0+1i) \
& =0^2+1^2
end{aligned} \[1ex]
shadebox{ N(i) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
end{aligned} \[1ex]
shadebox{N(-i) = 1}
end{gathered}
end{equation}
end{document}
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
add a comment |
I propose this layout:
documentclass{article}
usepackage[utf8]{inputenc}%
usepackage{geometry}
usepackage[table, svgnames]{xcolor}
usepackage{mathtools}
colorlet{shadecolor}{Gainsboro!50! Lavender}
newcommand*shadebox[1]{%
colorbox{shadecolor}{hspace{1em}$displaystyle #1 $hspace{1em}}}
begin{document}
begin{equation}
begin{gathered}
begin{aligned}
N(1) & =N(1+0i)\
& =1^2+0^2
end{aligned} \[1.5ex]
shadebox{N(1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
end{aligned} \[1ex]
shadebox{N(-1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(i) & =N(0+1i) \
& =0^2+1^2
end{aligned} \[1ex]
shadebox{ N(i) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
end{aligned} \[1ex]
shadebox{N(-i) = 1}
end{gathered}
end{equation}
end{document}
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
add a comment |
I propose this layout:
documentclass{article}
usepackage[utf8]{inputenc}%
usepackage{geometry}
usepackage[table, svgnames]{xcolor}
usepackage{mathtools}
colorlet{shadecolor}{Gainsboro!50! Lavender}
newcommand*shadebox[1]{%
colorbox{shadecolor}{hspace{1em}$displaystyle #1 $hspace{1em}}}
begin{document}
begin{equation}
begin{gathered}
begin{aligned}
N(1) & =N(1+0i)\
& =1^2+0^2
end{aligned} \[1.5ex]
shadebox{N(1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
end{aligned} \[1ex]
shadebox{N(-1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(i) & =N(0+1i) \
& =0^2+1^2
end{aligned} \[1ex]
shadebox{ N(i) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
end{aligned} \[1ex]
shadebox{N(-i) = 1}
end{gathered}
end{equation}
end{document}
I propose this layout:
documentclass{article}
usepackage[utf8]{inputenc}%
usepackage{geometry}
usepackage[table, svgnames]{xcolor}
usepackage{mathtools}
colorlet{shadecolor}{Gainsboro!50! Lavender}
newcommand*shadebox[1]{%
colorbox{shadecolor}{hspace{1em}$displaystyle #1 $hspace{1em}}}
begin{document}
begin{equation}
begin{gathered}
begin{aligned}
N(1) & =N(1+0i)\
& =1^2+0^2
end{aligned} \[1.5ex]
shadebox{N(1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-1) & =N(-1+0i) \
& =(-1)^2+0^2
end{aligned} \[1ex]
shadebox{N(-1) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(i) & =N(0+1i) \
& =0^2+1^2
end{aligned} \[1ex]
shadebox{ N(i) = 1}
end{gathered}
qquad
begin{gathered}
begin{aligned}
N(-i) & =N(0-1i) \
& =0^2+(-1)^2
end{aligned} \[1ex]
shadebox{N(-i) = 1}
end{gathered}
end{equation}
end{document}
answered 22 mins ago
BernardBernard
178k779211
178k779211
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
add a comment |
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
1
1
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
Very nice. The parfum of the lavander is fantastic and also the color :-)
– Sebastiano
18 mins ago
1
1
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
I like it because I feel it adds some freshness to the Gainsboro grey (b.t.w., is there a Leonardo grey? ;o)
– Bernard
12 mins ago
add a comment |
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Maybe use an
array
environment?– leandriis
1 hour ago
The only problem is that I don't know anything about arrays in Latex. I can look them up and see what I can find but are there any other suggestions that come to mind?
– Alex Adinolfi
1 hour ago