Deconstruction is ambiguous Announcing the arrival of Valued Associate #679: Cesar Manara ...
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Deconstruction is ambiguous
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I have a vector class with two deconstruction methods as follows:
public readonly struct Vector2
{
public readonly double X, Y;
...
public void Deconstruct( out double x, out double y )
{
x = this.X;
y = this.Y;
}
public void Deconstruct( out Vector2 unitVector, out double length )
{
length = this.Length;
unitVector = this / length;
}
}
Somewhere else I have:
Vector2 foo = ...
(Vector2 dir, double len) = foo;
This gives me:
CS0121: The call is ambiguous between the following methods or properties: 'Vector2.Deconstruct(out double, out double)' and 'Vector2.Deconstruct(out Vector2, out double)'
How is this ambiguous?
Edit: Calling Deconstruct manually works fine:
foo.Deconstruct( out Vector2 dir, out double len );
c# c#-7.3
asked 4 hours ago
ChrisChris
4,7381025
add a comment |
I have a vector class with two deconstruction methods as follows:
public readonly struct Vector2
{
public readonly double X, Y;
...
public void Deconstruct( out double x, out double y )
{
x = this.X;
y = this.Y;
}
public void Deconstruct( out Vector2 unitVector, out double length )
{
length = this.Length;
unitVector = this / length;
}
}
Somewhere else I have:
Vector2 foo = ...
(Vector2 dir, double len) = foo;
This gives me:
CS0121: The call is ambiguous between the following methods or properties: 'Vector2.Deconstruct(out double, out double)' and 'Vector2.Deconstruct(out Vector2, out double)'
How is this ambiguous?
Edit: Calling Deconstruct manually works fine:
foo.Deconstruct( out Vector2 dir, out double len );
c# c#-7.3
asked 4 hours ago
ChrisChris
4,7381025
If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago
add a comment |
I have a vector class with two deconstruction methods as follows:
public readonly struct Vector2
{
public readonly double X, Y;
...
public void Deconstruct( out double x, out double y )
{
x = this.X;
y = this.Y;
}
public void Deconstruct( out Vector2 unitVector, out double length )
{
length = this.Length;
unitVector = this / length;
}
}
Somewhere else I have:
Vector2 foo = ...
(Vector2 dir, double len) = foo;
This gives me:
CS0121: The call is ambiguous between the following methods or properties: 'Vector2.Deconstruct(out double, out double)' and 'Vector2.Deconstruct(out Vector2, out double)'
How is this ambiguous?
Edit: Calling Deconstruct manually works fine:
foo.Deconstruct( out Vector2 dir, out double len );
c# c#-7.3
asked 4 hours ago
ChrisChris
4,7381025
I have a vector class with two deconstruction methods as follows:
public readonly struct Vector2
{
public readonly double X, Y;
...
public void Deconstruct( out double x, out double y )
{
x = this.X;
y = this.Y;
}
public void Deconstruct( out Vector2 unitVector, out double length )
{
length = this.Length;
unitVector = this / length;
}
}
Somewhere else I have:
Vector2 foo = ...
(Vector2 dir, double len) = foo;
This gives me:
CS0121: The call is ambiguous between the following methods or properties: 'Vector2.Deconstruct(out double, out double)' and 'Vector2.Deconstruct(out Vector2, out double)'
How is this ambiguous?
Edit: Calling Deconstruct manually works fine:
foo.Deconstruct( out Vector2 dir, out double len );
c# c#-7.3
c# c#-7.3
asked 4 hours ago
ChrisChris
4,7381025
asked 4 hours ago
ChrisChris
4,7381025
edited 4 hours ago
Chris
asked 4 hours ago
ChrisChris
4,7381025
asked 4 hours ago
ChrisChris
4,7381025
asked 4 hours ago
ChrisChris
4,7381025
4,7381025
If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago
add a comment |
If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago
If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago
If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
This is by design in C#. Overloads of Deconstruct must have different arity (number of parameters), otherwise they are ambiguous.
Pattern-matching does not have a left-hand-side. More elaborate
pattern-matching scheme is to have a parenthesized list of patterns to
match, and we use the number of patterns to decide which Deconstruct
to use.
- Neal Gafter https://github.com/dotnet/csharplang/issues/1998#issuecomment-438472660
answered 4 hours ago
AsikAsik
14.4k349105
1
That is thoroughly disappointing!
– Chris
4 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is by design in C#. Overloads of Deconstruct must have different arity (number of parameters), otherwise they are ambiguous.
Pattern-matching does not have a left-hand-side. More elaborate
pattern-matching scheme is to have a parenthesized list of patterns to
match, and we use the number of patterns to decide which Deconstruct
to use.
- Neal Gafter https://github.com/dotnet/csharplang/issues/1998#issuecomment-438472660
answered 4 hours ago
AsikAsik
14.4k349105
1
That is thoroughly disappointing!
– Chris
4 hours ago
add a comment |
This is by design in C#. Overloads of Deconstruct must have different arity (number of parameters), otherwise they are ambiguous.
Pattern-matching does not have a left-hand-side. More elaborate
pattern-matching scheme is to have a parenthesized list of patterns to
match, and we use the number of patterns to decide which Deconstruct
to use.
- Neal Gafter https://github.com/dotnet/csharplang/issues/1998#issuecomment-438472660
answered 4 hours ago
AsikAsik
14.4k349105
1
That is thoroughly disappointing!
– Chris
4 hours ago
add a comment |
This is by design in C#. Overloads of Deconstruct must have different arity (number of parameters), otherwise they are ambiguous.
Pattern-matching does not have a left-hand-side. More elaborate
pattern-matching scheme is to have a parenthesized list of patterns to
match, and we use the number of patterns to decide which Deconstruct
to use.
- Neal Gafter https://github.com/dotnet/csharplang/issues/1998#issuecomment-438472660
answered 4 hours ago
AsikAsik
14.4k349105
This is by design in C#. Overloads of Deconstruct must have different arity (number of parameters), otherwise they are ambiguous.
Pattern-matching does not have a left-hand-side. More elaborate
pattern-matching scheme is to have a parenthesized list of patterns to
match, and we use the number of patterns to decide which Deconstruct
to use.
- Neal Gafter https://github.com/dotnet/csharplang/issues/1998#issuecomment-438472660
answered 4 hours ago
AsikAsik
14.4k349105
edited 3 hours ago
answered 4 hours ago
AsikAsik
14.4k349105
answered 4 hours ago
AsikAsik
14.4k349105
answered 4 hours ago
AsikAsik
14.4k349105
14.4k349105
1
That is thoroughly disappointing!
– Chris
4 hours ago
add a comment |
1
That is thoroughly disappointing!
– Chris
4 hours ago
1
1
That is thoroughly disappointing!
– Chris
4 hours ago
That is thoroughly disappointing!
– Chris
4 hours ago
add a comment |
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If your Vector class had implicit conversion to/from a double, say, then this would be ambiguous.
– Ian Mercer
3 hours ago