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Deal the cards to the players
Create chunks from an arraySimple One Game BlackjackName the poker hand - 7 cards editionCompare two poker handsDetermine the winner of a game of WarHelp me cheat at CheatScore a hand of HeartsGolf an unbeatable chopsticks bot1326 starting hold'em combosBadugi, Who Wins?Deal an ASCII Deck
$begingroup$
Tonight is card game night! You are the dealer and your task is to write a program to deal the cards to the players.
Given an array of card and a number of player, you need to split the array into hand for each player.
Rules
Your program will receive an non-empty array A , as well as a non-zero positive integer n. The array should then be split into n hands, if the length of the string isn't divisible by n any leftover at the end should be distributed as evenly as possible.
- If
nis equals to 1, you will need to return an array of arrayA
If
nis greater than the length ofA, you will need to return every hands and an empty hand. ifn = 4andarray A = [1,2,3], you should return[[1],[2],[3]]or[[1],[2],[3],[]]. You are free to handle the empty hand with empty, undefined or null.The array can contain any type rather than a number.
You should not change order (or direction) of any item from left to right. For example
if n = 2andA= [1,2,3]. Any result rather than[[1,3],[2]]will be invalid.
Test Cases
n A Output
1 [1,2,3,4,5,6] [[1,2,3,4,5,6]]
2 [1,2,3,4,5,6] [[1,3,5],[2,4,6]]
3 [1,2,3,4,5,6] [[1,4],[2,5],[3,6]]
4 [1,2,3,4,5,6] [[1,5],[2,6],[3],[4]]
7 [1,2,3,4,5,6] [[1],[2],[3],[4],[5],[6]] // or [[1],[2],[3],[4],[5],[6],[]]
Demo
def deal(cards, n):
i = 0
players = [[] for _ in range(n)]
for card in cards:
players[i % n].append(card)
i += 1
return players
hands = deal([1,2,3,4,5,6], 2)
for hand in hands:
print(hand)
Try it online!
This is code-golf, so you the shortest bytes of each language will be the winner.
Inspired from Create chunks from array by chau giang
code-golf array-manipulation
asked 1 hour ago
aloisdgaloisdg
1,4891122
$endgroup$
|
show 9 more comments
$begingroup$
Tonight is card game night! You are the dealer and your task is to write a program to deal the cards to the players.
Given an array of card and a number of player, you need to split the array into hand for each player.
Rules
Your program will receive an non-empty array A , as well as a non-zero positive integer n. The array should then be split into n hands, if the length of the string isn't divisible by n any leftover at the end should be distributed as evenly as possible.
- If
nis equals to 1, you will need to return an array of arrayA
If
nis greater than the length ofA, you will need to return every hands and an empty hand. ifn = 4andarray A = [1,2,3], you should return[[1],[2],[3]]or[[1],[2],[3],[]]. You are free to handle the empty hand with empty, undefined or null.The array can contain any type rather than a number.
You should not change order (or direction) of any item from left to right. For example
if n = 2andA= [1,2,3]. Any result rather than[[1,3],[2]]will be invalid.
Test Cases
n A Output
1 [1,2,3,4,5,6] [[1,2,3,4,5,6]]
2 [1,2,3,4,5,6] [[1,3,5],[2,4,6]]
3 [1,2,3,4,5,6] [[1,4],[2,5],[3,6]]
4 [1,2,3,4,5,6] [[1,5],[2,6],[3],[4]]
7 [1,2,3,4,5,6] [[1],[2],[3],[4],[5],[6]] // or [[1],[2],[3],[4],[5],[6],[]]
Demo
def deal(cards, n):
i = 0
players = [[] for _ in range(n)]
for card in cards:
players[i % n].append(card)
i += 1
return players
hands = deal([1,2,3,4,5,6], 2)
for hand in hands:
print(hand)
Try it online!
This is code-golf, so you the shortest bytes of each language will be the winner.
Inspired from Create chunks from array by chau giang
code-golf array-manipulation
asked 1 hour ago
aloisdgaloisdg
1,4891122
$endgroup$
1
$begingroup$
All the test cases seem to splitAintonchunks rather than into chunks of sizen.
$endgroup$
– Adám
39 mins ago
1
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
1
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
1
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
3
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago
|
show 9 more comments
$begingroup$
Tonight is card game night! You are the dealer and your task is to write a program to deal the cards to the players.
Given an array of card and a number of player, you need to split the array into hand for each player.
Rules
Your program will receive an non-empty array A , as well as a non-zero positive integer n. The array should then be split into n hands, if the length of the string isn't divisible by n any leftover at the end should be distributed as evenly as possible.
- If
nis equals to 1, you will need to return an array of arrayA
If
nis greater than the length ofA, you will need to return every hands and an empty hand. ifn = 4andarray A = [1,2,3], you should return[[1],[2],[3]]or[[1],[2],[3],[]]. You are free to handle the empty hand with empty, undefined or null.The array can contain any type rather than a number.
You should not change order (or direction) of any item from left to right. For example
if n = 2andA= [1,2,3]. Any result rather than[[1,3],[2]]will be invalid.
Test Cases
n A Output
1 [1,2,3,4,5,6] [[1,2,3,4,5,6]]
2 [1,2,3,4,5,6] [[1,3,5],[2,4,6]]
3 [1,2,3,4,5,6] [[1,4],[2,5],[3,6]]
4 [1,2,3,4,5,6] [[1,5],[2,6],[3],[4]]
7 [1,2,3,4,5,6] [[1],[2],[3],[4],[5],[6]] // or [[1],[2],[3],[4],[5],[6],[]]
Demo
def deal(cards, n):
i = 0
players = [[] for _ in range(n)]
for card in cards:
players[i % n].append(card)
i += 1
return players
hands = deal([1,2,3,4,5,6], 2)
for hand in hands:
print(hand)
Try it online!
This is code-golf, so you the shortest bytes of each language will be the winner.
Inspired from Create chunks from array by chau giang
code-golf array-manipulation
asked 1 hour ago
aloisdgaloisdg
1,4891122
$endgroup$
Tonight is card game night! You are the dealer and your task is to write a program to deal the cards to the players.
Given an array of card and a number of player, you need to split the array into hand for each player.
Rules
Your program will receive an non-empty array A , as well as a non-zero positive integer n. The array should then be split into n hands, if the length of the string isn't divisible by n any leftover at the end should be distributed as evenly as possible.
- If
nis equals to 1, you will need to return an array of arrayA
If
nis greater than the length ofA, you will need to return every hands and an empty hand. ifn = 4andarray A = [1,2,3], you should return[[1],[2],[3]]or[[1],[2],[3],[]]. You are free to handle the empty hand with empty, undefined or null.The array can contain any type rather than a number.
You should not change order (or direction) of any item from left to right. For example
if n = 2andA= [1,2,3]. Any result rather than[[1,3],[2]]will be invalid.
Test Cases
n A Output
1 [1,2,3,4,5,6] [[1,2,3,4,5,6]]
2 [1,2,3,4,5,6] [[1,3,5],[2,4,6]]
3 [1,2,3,4,5,6] [[1,4],[2,5],[3,6]]
4 [1,2,3,4,5,6] [[1,5],[2,6],[3],[4]]
7 [1,2,3,4,5,6] [[1],[2],[3],[4],[5],[6]] // or [[1],[2],[3],[4],[5],[6],[]]
Demo
def deal(cards, n):
i = 0
players = [[] for _ in range(n)]
for card in cards:
players[i % n].append(card)
i += 1
return players
hands = deal([1,2,3,4,5,6], 2)
for hand in hands:
print(hand)
Try it online!
This is code-golf, so you the shortest bytes of each language will be the winner.
Inspired from Create chunks from array by chau giang
code-golf array-manipulation
code-golf array-manipulation
asked 1 hour ago
aloisdgaloisdg
1,4891122
asked 1 hour ago
aloisdgaloisdg
1,4891122
edited 4 mins ago
aloisdg
asked 1 hour ago
aloisdgaloisdg
1,4891122
asked 1 hour ago
aloisdgaloisdg
1,4891122
asked 1 hour ago
aloisdgaloisdg
1,4891122
1,4891122
1
$begingroup$
All the test cases seem to splitAintonchunks rather than into chunks of sizen.
$endgroup$
– Adám
39 mins ago
1
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
1
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
1
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
3
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago
|
show 9 more comments
1
$begingroup$
All the test cases seem to splitAintonchunks rather than into chunks of sizen.
$endgroup$
– Adám
39 mins ago
1
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
1
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
1
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
3
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago
1
1
$begingroup$
All the test cases seem to split
A into n chunks rather than into chunks of size n.$endgroup$
– Adám
39 mins ago
$begingroup$
All the test cases seem to split
A into n chunks rather than into chunks of size n.$endgroup$
– Adám
39 mins ago
1
1
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
1
1
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
1
1
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
3
3
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago
|
show 9 more comments
5 Answers
5
active
oldest
votes
$begingroup$
Japt, 2 bytes
Takes the array as the first input.
óV
Try it
answered 43 mins ago
ShaggyShaggy
19.4k21667
$endgroup$
add a comment |
$begingroup$
R, 46 25 bytes
function(A,n)split(A,1:n)
Try it online!
splits A into groups defined by 1:n, recycling 1:n until it matches length with A.
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
$endgroup$
add a comment |
$begingroup$
Python 2, 37 bytes
Code:
lambda x,n:[x[i::n]for i in range(n)]
Try it online!
answered 31 mins ago
AdnanAdnan
35.7k562225
$endgroup$
add a comment |
$begingroup$
Perl 6, 33 24 bytes
->b{*.classify:{$++%b}}
Try it online!
Anonymous curried code block that takes a number and returns a Whatever lambda that takes a list and returns a list of lists. This takes the second option when given a number larger than the length of lists, e.g. f(4)([1,2,3]) returns [[1],[2],[3]]
Explanation:
->b{ } # Anonymous code block that takes a number
* # And returns a Whatever lambda
.classify # That groups by
:{$++%b} # The index modulo the number
answered 50 mins ago
Jo KingJo King
24.3k357125
$endgroup$
add a comment |
$begingroup$
C# (Visual C# Interactive Compiler), 43 bytes
a=>b=>{int i=0;return a.GroupBy(_=>i++%b);}
Try it online!
answered 52 mins ago
aloisdgaloisdg
1,4891122
$endgroup$
$begingroup$
@JoKing[1,2,3], 4should output[[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.
$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Japt, 2 bytes
Takes the array as the first input.
óV
Try it
answered 43 mins ago
ShaggyShaggy
19.4k21667
$endgroup$
add a comment |
$begingroup$
Japt, 2 bytes
Takes the array as the first input.
óV
Try it
answered 43 mins ago
ShaggyShaggy
19.4k21667
$endgroup$
add a comment |
$begingroup$
Japt, 2 bytes
Takes the array as the first input.
óV
Try it
answered 43 mins ago
ShaggyShaggy
19.4k21667
$endgroup$
Japt, 2 bytes
Takes the array as the first input.
óV
Try it
answered 43 mins ago
ShaggyShaggy
19.4k21667
answered 43 mins ago
ShaggyShaggy
19.4k21667
answered 43 mins ago
ShaggyShaggy
19.4k21667
answered 43 mins ago
ShaggyShaggy
19.4k21667
19.4k21667
add a comment |
add a comment |
$begingroup$
R, 46 25 bytes
function(A,n)split(A,1:n)
Try it online!
splits A into groups defined by 1:n, recycling 1:n until it matches length with A.
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
$endgroup$
add a comment |
$begingroup$
R, 46 25 bytes
function(A,n)split(A,1:n)
Try it online!
splits A into groups defined by 1:n, recycling 1:n until it matches length with A.
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
$endgroup$
add a comment |
$begingroup$
R, 46 25 bytes
function(A,n)split(A,1:n)
Try it online!
splits A into groups defined by 1:n, recycling 1:n until it matches length with A.
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
$endgroup$
R, 46 25 bytes
function(A,n)split(A,1:n)
Try it online!
splits A into groups defined by 1:n, recycling 1:n until it matches length with A.
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
edited 33 mins ago
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
answered 51 mins ago
GiuseppeGiuseppe
16.6k31052
16.6k31052
add a comment |
add a comment |
$begingroup$
Python 2, 37 bytes
Code:
lambda x,n:[x[i::n]for i in range(n)]
Try it online!
answered 31 mins ago
AdnanAdnan
35.7k562225
$endgroup$
add a comment |
$begingroup$
Python 2, 37 bytes
Code:
lambda x,n:[x[i::n]for i in range(n)]
Try it online!
answered 31 mins ago
AdnanAdnan
35.7k562225
$endgroup$
add a comment |
$begingroup$
Python 2, 37 bytes
Code:
lambda x,n:[x[i::n]for i in range(n)]
Try it online!
answered 31 mins ago
AdnanAdnan
35.7k562225
$endgroup$
Python 2, 37 bytes
Code:
lambda x,n:[x[i::n]for i in range(n)]
Try it online!
answered 31 mins ago
AdnanAdnan
35.7k562225
answered 31 mins ago
AdnanAdnan
35.7k562225
answered 31 mins ago
AdnanAdnan
35.7k562225
answered 31 mins ago
AdnanAdnan
35.7k562225
35.7k562225
add a comment |
add a comment |
$begingroup$
Perl 6, 33 24 bytes
->b{*.classify:{$++%b}}
Try it online!
Anonymous curried code block that takes a number and returns a Whatever lambda that takes a list and returns a list of lists. This takes the second option when given a number larger than the length of lists, e.g. f(4)([1,2,3]) returns [[1],[2],[3]]
Explanation:
->b{ } # Anonymous code block that takes a number
* # And returns a Whatever lambda
.classify # That groups by
:{$++%b} # The index modulo the number
answered 50 mins ago
Jo KingJo King
24.3k357125
$endgroup$
add a comment |
$begingroup$
Perl 6, 33 24 bytes
->b{*.classify:{$++%b}}
Try it online!
Anonymous curried code block that takes a number and returns a Whatever lambda that takes a list and returns a list of lists. This takes the second option when given a number larger than the length of lists, e.g. f(4)([1,2,3]) returns [[1],[2],[3]]
Explanation:
->b{ } # Anonymous code block that takes a number
* # And returns a Whatever lambda
.classify # That groups by
:{$++%b} # The index modulo the number
answered 50 mins ago
Jo KingJo King
24.3k357125
$endgroup$
add a comment |
$begingroup$
Perl 6, 33 24 bytes
->b{*.classify:{$++%b}}
Try it online!
Anonymous curried code block that takes a number and returns a Whatever lambda that takes a list and returns a list of lists. This takes the second option when given a number larger than the length of lists, e.g. f(4)([1,2,3]) returns [[1],[2],[3]]
Explanation:
->b{ } # Anonymous code block that takes a number
* # And returns a Whatever lambda
.classify # That groups by
:{$++%b} # The index modulo the number
answered 50 mins ago
Jo KingJo King
24.3k357125
$endgroup$
Perl 6, 33 24 bytes
->b{*.classify:{$++%b}}
Try it online!
Anonymous curried code block that takes a number and returns a Whatever lambda that takes a list and returns a list of lists. This takes the second option when given a number larger than the length of lists, e.g. f(4)([1,2,3]) returns [[1],[2],[3]]
Explanation:
->b{ } # Anonymous code block that takes a number
* # And returns a Whatever lambda
.classify # That groups by
:{$++%b} # The index modulo the number
answered 50 mins ago
Jo KingJo King
24.3k357125
edited 17 mins ago
answered 50 mins ago
Jo KingJo King
24.3k357125
answered 50 mins ago
Jo KingJo King
24.3k357125
answered 50 mins ago
Jo KingJo King
24.3k357125
24.3k357125
add a comment |
add a comment |
$begingroup$
C# (Visual C# Interactive Compiler), 43 bytes
a=>b=>{int i=0;return a.GroupBy(_=>i++%b);}
Try it online!
answered 52 mins ago
aloisdgaloisdg
1,4891122
$endgroup$
$begingroup$
@JoKing[1,2,3], 4should output[[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.
$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
add a comment |
$begingroup$
C# (Visual C# Interactive Compiler), 43 bytes
a=>b=>{int i=0;return a.GroupBy(_=>i++%b);}
Try it online!
answered 52 mins ago
aloisdgaloisdg
1,4891122
$endgroup$
$begingroup$
@JoKing[1,2,3], 4should output[[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.
$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
add a comment |
$begingroup$
C# (Visual C# Interactive Compiler), 43 bytes
a=>b=>{int i=0;return a.GroupBy(_=>i++%b);}
Try it online!
answered 52 mins ago
aloisdgaloisdg
1,4891122
$endgroup$
C# (Visual C# Interactive Compiler), 43 bytes
a=>b=>{int i=0;return a.GroupBy(_=>i++%b);}
Try it online!
answered 52 mins ago
aloisdgaloisdg
1,4891122
answered 52 mins ago
aloisdgaloisdg
1,4891122
answered 52 mins ago
aloisdgaloisdg
1,4891122
answered 52 mins ago
aloisdgaloisdg
1,4891122
1,4891122
$begingroup$
@JoKing[1,2,3], 4should output[[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.
$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
add a comment |
$begingroup$
@JoKing[1,2,3], 4should output[[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.
$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
$begingroup$
@JoKing
[1,2,3], 4 should output [[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.$endgroup$
– aloisdg
44 mins ago
$begingroup$
@JoKing
[1,2,3], 4 should output [[1],[2],[3]]. You are dealing 3 cards to 4 players. I will update the main question.$endgroup$
– aloisdg
44 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
$begingroup$
It's generally discouraged to post solutions to your own challenges immediately.
$endgroup$
– Shaggy
42 mins ago
1
1
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Shaggy ok I will take it into account for the next time. It is fine on so and rpg but I guess the competitive aspect of codegolf made it a bit unfair to self post directly. Make sense.
$endgroup$
– aloisdg
40 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
$begingroup$
@Joe king you are right! I made a typo :/
$endgroup$
– aloisdg
39 mins ago
add a comment |
If this is an answer to a challenge…
…Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.
…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
Explanations of your answer make it more interesting to read and are very much encouraged.…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.
More generally…
…Please make sure to answer the question and provide sufficient detail.
…Avoid asking for help, clarification or responding to other answers (use comments instead).
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1
$begingroup$
All the test cases seem to split
Aintonchunks rather than into chunks of sizen.$endgroup$
– Adám
39 mins ago
1
$begingroup$
should be give to a player as much as possible means should be distributed as evenly as possible, right? If so, please edit to actually say so.
$endgroup$
– Adám
29 mins ago
1
$begingroup$
@aloisdg Great, but now your first bulleted rule is unnecessary and wrong.
$endgroup$
– Adám
26 mins ago
1
$begingroup$
you will need to return every hands and an empty hand contradicts the last test case's first result possibility.
$endgroup$
– Adám
23 mins ago
3
$begingroup$
In the future I'd recommend using the Sandbox to iron out problems and gauge community feedback before posting your question to main
$endgroup$
– Jo King
22 mins ago