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In a Spin are Both Wings Stalled?
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$begingroup$
I missed a test question which asked that if an airplane was spinning to the left which wing was stalled. The supposed correct answer was that both wings are stalled (I had answered that the left wing only was stalled). However after looking at the this article on Wikipedia it seems to indicate that only one wing needs to be stalled to spin:
In a normal spin, the wing on the inside of the turn stalls while the outside wing remains flying. It is possible for both wings to stall, but the angle of attack of each wing, and consequently its lift and drag, are different. Either situation causes the aircraft to autorotate toward the stalled wing due to its higher drag and loss of lift.
So my question is was it fair for me to have missed that test question since according to Wikipedia a spin can occur with only one wing stalled?
spins faa-knowledge-test
$endgroup$
add a comment |
$begingroup$
I missed a test question which asked that if an airplane was spinning to the left which wing was stalled. The supposed correct answer was that both wings are stalled (I had answered that the left wing only was stalled). However after looking at the this article on Wikipedia it seems to indicate that only one wing needs to be stalled to spin:
In a normal spin, the wing on the inside of the turn stalls while the outside wing remains flying. It is possible for both wings to stall, but the angle of attack of each wing, and consequently its lift and drag, are different. Either situation causes the aircraft to autorotate toward the stalled wing due to its higher drag and loss of lift.
So my question is was it fair for me to have missed that test question since according to Wikipedia a spin can occur with only one wing stalled?
spins faa-knowledge-test
$endgroup$
add a comment |
$begingroup$
I missed a test question which asked that if an airplane was spinning to the left which wing was stalled. The supposed correct answer was that both wings are stalled (I had answered that the left wing only was stalled). However after looking at the this article on Wikipedia it seems to indicate that only one wing needs to be stalled to spin:
In a normal spin, the wing on the inside of the turn stalls while the outside wing remains flying. It is possible for both wings to stall, but the angle of attack of each wing, and consequently its lift and drag, are different. Either situation causes the aircraft to autorotate toward the stalled wing due to its higher drag and loss of lift.
So my question is was it fair for me to have missed that test question since according to Wikipedia a spin can occur with only one wing stalled?
spins faa-knowledge-test
$endgroup$
I missed a test question which asked that if an airplane was spinning to the left which wing was stalled. The supposed correct answer was that both wings are stalled (I had answered that the left wing only was stalled). However after looking at the this article on Wikipedia it seems to indicate that only one wing needs to be stalled to spin:
In a normal spin, the wing on the inside of the turn stalls while the outside wing remains flying. It is possible for both wings to stall, but the angle of attack of each wing, and consequently its lift and drag, are different. Either situation causes the aircraft to autorotate toward the stalled wing due to its higher drag and loss of lift.
So my question is was it fair for me to have missed that test question since according to Wikipedia a spin can occur with only one wing stalled?
spins faa-knowledge-test
spins faa-knowledge-test
asked 2 hours ago
DLHDLH
2,593829
2,593829
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
No, one wing has at least partially attached flow. How else would there be a rolling and yawing moment which keeps the spin movement alive?
During a spin the aircraft experiences a linear variation in angle of attack over span. The pitch attitude is between 40° and 60° nose-down, and the local angle of attack is 90° minus the pitch angle, which is between 50° and 30°, at the center wing. Move outward from there and the angle of attack increases on the retarding side and decreases on the advancing side.
As a consequence, the outer advancing wing will experience a moderate angle of attack which can even become negative at the tip. Therefore, a sizeable portion of that wing side has attached flow with high lift and low drag. On the other side the angle of attack grows to 90° and beyond, so the wing is fully separated and the aerodynamic force is normal to the wing surface. See below for a diagram of the flow direction: The dark blue vector is from the falling motion and the red vector is the product of the yawing moment $omega_z$ times the wing station y. Together they combine to the green vector which produces a resulting aerodynamic force R:

On the left is the retarding wing and on the right the advancing wing. Note that the aerodynamic force is in line with the flow vector on the retarding wing with its fully separated flow while the aerodynamic force is normal to the flow vector due to the attached flow on the advancing wing. The difference in the local forces produces a yawing and rolling moment which balances with the damping forces. If there would not be such an asymmetry, the motion would die down quickly.
Even in a flat spin, where the pitch attitude is around 0° (resulting in 90° angle of attack at the center wing), the advancing side of a moderate to high aspect ratio wing produces some nose thrust from partially attached flow. How else would the aircraft keep spinnig? Low aspect ratio designs produce a propelling nose vortex on the forward fuselage which keeps the motion alive.
$endgroup$
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
add a comment |
$begingroup$
Yes, both are stalled.
I guess a nit-pick is on "what is stalled"? I adopt that you are at or beyond the point that an increase in AOA results in an increase in lift. That's the top of the blue curve in the plot below.
At low angles of attack (AOA) planes are naturally stable in roll. The downgoing wing sees a higher AOA which results in more lift, and a restoring force. The upgoing wings sees a lower AOA, and less lift, so it is stabilizing too.
At a high AOA, though, you are operating on the backside of the wing lift diagram. In the picture below, this would be at and beyond 20 degrees AOA.

Now, the upgoing wing sees more lift, which leads to positively reinforcing going up. Same but opposite on the downgoing. It sees less lift.
Also, the red line shows drag. That downgoing wing (on inside of the spin) sees a great increase in drag, which will lead to a yaw towards that wing, i.e., pro-spin.
So to get in the situation where a roll/yaw movement is positively reinforcing, you need to be in stalled AOA. You might start with just one wing, you'll get to both.
JMHO!
$endgroup$
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
add a comment |
$begingroup$
A spin is an autorotation that requires an asymmetric thrust force to sustain. This requires the wing span to be anchored at one end by drag, with the other end developing enough thrust to overcome the (rather weak) stabilizing force of the vertical fin and drive that end forward, rotating the plane. The AOA is highest at the inboard end and decreases as you move outboard due to the higher forward velocity. At some point along the span, the outer end is unstalled or only semi-stalled and is making at least some amount of lift/thrust.
$endgroup$
add a comment |
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3 Answers
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3 Answers
3
active
oldest
votes
active
oldest
votes
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oldest
votes
$begingroup$
No, one wing has at least partially attached flow. How else would there be a rolling and yawing moment which keeps the spin movement alive?
During a spin the aircraft experiences a linear variation in angle of attack over span. The pitch attitude is between 40° and 60° nose-down, and the local angle of attack is 90° minus the pitch angle, which is between 50° and 30°, at the center wing. Move outward from there and the angle of attack increases on the retarding side and decreases on the advancing side.
As a consequence, the outer advancing wing will experience a moderate angle of attack which can even become negative at the tip. Therefore, a sizeable portion of that wing side has attached flow with high lift and low drag. On the other side the angle of attack grows to 90° and beyond, so the wing is fully separated and the aerodynamic force is normal to the wing surface. See below for a diagram of the flow direction: The dark blue vector is from the falling motion and the red vector is the product of the yawing moment $omega_z$ times the wing station y. Together they combine to the green vector which produces a resulting aerodynamic force R:

On the left is the retarding wing and on the right the advancing wing. Note that the aerodynamic force is in line with the flow vector on the retarding wing with its fully separated flow while the aerodynamic force is normal to the flow vector due to the attached flow on the advancing wing. The difference in the local forces produces a yawing and rolling moment which balances with the damping forces. If there would not be such an asymmetry, the motion would die down quickly.
Even in a flat spin, where the pitch attitude is around 0° (resulting in 90° angle of attack at the center wing), the advancing side of a moderate to high aspect ratio wing produces some nose thrust from partially attached flow. How else would the aircraft keep spinnig? Low aspect ratio designs produce a propelling nose vortex on the forward fuselage which keeps the motion alive.
$endgroup$
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
add a comment |
$begingroup$
No, one wing has at least partially attached flow. How else would there be a rolling and yawing moment which keeps the spin movement alive?
During a spin the aircraft experiences a linear variation in angle of attack over span. The pitch attitude is between 40° and 60° nose-down, and the local angle of attack is 90° minus the pitch angle, which is between 50° and 30°, at the center wing. Move outward from there and the angle of attack increases on the retarding side and decreases on the advancing side.
As a consequence, the outer advancing wing will experience a moderate angle of attack which can even become negative at the tip. Therefore, a sizeable portion of that wing side has attached flow with high lift and low drag. On the other side the angle of attack grows to 90° and beyond, so the wing is fully separated and the aerodynamic force is normal to the wing surface. See below for a diagram of the flow direction: The dark blue vector is from the falling motion and the red vector is the product of the yawing moment $omega_z$ times the wing station y. Together they combine to the green vector which produces a resulting aerodynamic force R:

On the left is the retarding wing and on the right the advancing wing. Note that the aerodynamic force is in line with the flow vector on the retarding wing with its fully separated flow while the aerodynamic force is normal to the flow vector due to the attached flow on the advancing wing. The difference in the local forces produces a yawing and rolling moment which balances with the damping forces. If there would not be such an asymmetry, the motion would die down quickly.
Even in a flat spin, where the pitch attitude is around 0° (resulting in 90° angle of attack at the center wing), the advancing side of a moderate to high aspect ratio wing produces some nose thrust from partially attached flow. How else would the aircraft keep spinnig? Low aspect ratio designs produce a propelling nose vortex on the forward fuselage which keeps the motion alive.
$endgroup$
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
add a comment |
$begingroup$
No, one wing has at least partially attached flow. How else would there be a rolling and yawing moment which keeps the spin movement alive?
During a spin the aircraft experiences a linear variation in angle of attack over span. The pitch attitude is between 40° and 60° nose-down, and the local angle of attack is 90° minus the pitch angle, which is between 50° and 30°, at the center wing. Move outward from there and the angle of attack increases on the retarding side and decreases on the advancing side.
As a consequence, the outer advancing wing will experience a moderate angle of attack which can even become negative at the tip. Therefore, a sizeable portion of that wing side has attached flow with high lift and low drag. On the other side the angle of attack grows to 90° and beyond, so the wing is fully separated and the aerodynamic force is normal to the wing surface. See below for a diagram of the flow direction: The dark blue vector is from the falling motion and the red vector is the product of the yawing moment $omega_z$ times the wing station y. Together they combine to the green vector which produces a resulting aerodynamic force R:

On the left is the retarding wing and on the right the advancing wing. Note that the aerodynamic force is in line with the flow vector on the retarding wing with its fully separated flow while the aerodynamic force is normal to the flow vector due to the attached flow on the advancing wing. The difference in the local forces produces a yawing and rolling moment which balances with the damping forces. If there would not be such an asymmetry, the motion would die down quickly.
Even in a flat spin, where the pitch attitude is around 0° (resulting in 90° angle of attack at the center wing), the advancing side of a moderate to high aspect ratio wing produces some nose thrust from partially attached flow. How else would the aircraft keep spinnig? Low aspect ratio designs produce a propelling nose vortex on the forward fuselage which keeps the motion alive.
$endgroup$
No, one wing has at least partially attached flow. How else would there be a rolling and yawing moment which keeps the spin movement alive?
During a spin the aircraft experiences a linear variation in angle of attack over span. The pitch attitude is between 40° and 60° nose-down, and the local angle of attack is 90° minus the pitch angle, which is between 50° and 30°, at the center wing. Move outward from there and the angle of attack increases on the retarding side and decreases on the advancing side.
As a consequence, the outer advancing wing will experience a moderate angle of attack which can even become negative at the tip. Therefore, a sizeable portion of that wing side has attached flow with high lift and low drag. On the other side the angle of attack grows to 90° and beyond, so the wing is fully separated and the aerodynamic force is normal to the wing surface. See below for a diagram of the flow direction: The dark blue vector is from the falling motion and the red vector is the product of the yawing moment $omega_z$ times the wing station y. Together they combine to the green vector which produces a resulting aerodynamic force R:

On the left is the retarding wing and on the right the advancing wing. Note that the aerodynamic force is in line with the flow vector on the retarding wing with its fully separated flow while the aerodynamic force is normal to the flow vector due to the attached flow on the advancing wing. The difference in the local forces produces a yawing and rolling moment which balances with the damping forces. If there would not be such an asymmetry, the motion would die down quickly.
Even in a flat spin, where the pitch attitude is around 0° (resulting in 90° angle of attack at the center wing), the advancing side of a moderate to high aspect ratio wing produces some nose thrust from partially attached flow. How else would the aircraft keep spinnig? Low aspect ratio designs produce a propelling nose vortex on the forward fuselage which keeps the motion alive.
edited 23 mins ago
answered 34 mins ago
Peter KämpfPeter Kämpf
161k12411654
161k12411654
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
add a comment |
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
So this is kind of like a helicopter rotor retreating blade stall where the retreating side can stall due to higher angle of attack?
$endgroup$
– DLH
15 mins ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
$begingroup$
@DLH: In a way, yes. But not cyclic, which causes all kind of funny oscillations from hysteresis on helicopter blades.
$endgroup$
– Peter Kämpf
23 secs ago
add a comment |
$begingroup$
Yes, both are stalled.
I guess a nit-pick is on "what is stalled"? I adopt that you are at or beyond the point that an increase in AOA results in an increase in lift. That's the top of the blue curve in the plot below.
At low angles of attack (AOA) planes are naturally stable in roll. The downgoing wing sees a higher AOA which results in more lift, and a restoring force. The upgoing wings sees a lower AOA, and less lift, so it is stabilizing too.
At a high AOA, though, you are operating on the backside of the wing lift diagram. In the picture below, this would be at and beyond 20 degrees AOA.

Now, the upgoing wing sees more lift, which leads to positively reinforcing going up. Same but opposite on the downgoing. It sees less lift.
Also, the red line shows drag. That downgoing wing (on inside of the spin) sees a great increase in drag, which will lead to a yaw towards that wing, i.e., pro-spin.
So to get in the situation where a roll/yaw movement is positively reinforcing, you need to be in stalled AOA. You might start with just one wing, you'll get to both.
JMHO!
$endgroup$
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
add a comment |
$begingroup$
Yes, both are stalled.
I guess a nit-pick is on "what is stalled"? I adopt that you are at or beyond the point that an increase in AOA results in an increase in lift. That's the top of the blue curve in the plot below.
At low angles of attack (AOA) planes are naturally stable in roll. The downgoing wing sees a higher AOA which results in more lift, and a restoring force. The upgoing wings sees a lower AOA, and less lift, so it is stabilizing too.
At a high AOA, though, you are operating on the backside of the wing lift diagram. In the picture below, this would be at and beyond 20 degrees AOA.

Now, the upgoing wing sees more lift, which leads to positively reinforcing going up. Same but opposite on the downgoing. It sees less lift.
Also, the red line shows drag. That downgoing wing (on inside of the spin) sees a great increase in drag, which will lead to a yaw towards that wing, i.e., pro-spin.
So to get in the situation where a roll/yaw movement is positively reinforcing, you need to be in stalled AOA. You might start with just one wing, you'll get to both.
JMHO!
$endgroup$
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
add a comment |
$begingroup$
Yes, both are stalled.
I guess a nit-pick is on "what is stalled"? I adopt that you are at or beyond the point that an increase in AOA results in an increase in lift. That's the top of the blue curve in the plot below.
At low angles of attack (AOA) planes are naturally stable in roll. The downgoing wing sees a higher AOA which results in more lift, and a restoring force. The upgoing wings sees a lower AOA, and less lift, so it is stabilizing too.
At a high AOA, though, you are operating on the backside of the wing lift diagram. In the picture below, this would be at and beyond 20 degrees AOA.

Now, the upgoing wing sees more lift, which leads to positively reinforcing going up. Same but opposite on the downgoing. It sees less lift.
Also, the red line shows drag. That downgoing wing (on inside of the spin) sees a great increase in drag, which will lead to a yaw towards that wing, i.e., pro-spin.
So to get in the situation where a roll/yaw movement is positively reinforcing, you need to be in stalled AOA. You might start with just one wing, you'll get to both.
JMHO!
$endgroup$
Yes, both are stalled.
I guess a nit-pick is on "what is stalled"? I adopt that you are at or beyond the point that an increase in AOA results in an increase in lift. That's the top of the blue curve in the plot below.
At low angles of attack (AOA) planes are naturally stable in roll. The downgoing wing sees a higher AOA which results in more lift, and a restoring force. The upgoing wings sees a lower AOA, and less lift, so it is stabilizing too.
At a high AOA, though, you are operating on the backside of the wing lift diagram. In the picture below, this would be at and beyond 20 degrees AOA.

Now, the upgoing wing sees more lift, which leads to positively reinforcing going up. Same but opposite on the downgoing. It sees less lift.
Also, the red line shows drag. That downgoing wing (on inside of the spin) sees a great increase in drag, which will lead to a yaw towards that wing, i.e., pro-spin.
So to get in the situation where a roll/yaw movement is positively reinforcing, you need to be in stalled AOA. You might start with just one wing, you'll get to both.
JMHO!
answered 2 hours ago
MikeYMikeY
54516
54516
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
add a comment |
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
2
2
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
I think this is a good answer. I've been reading up on spins. While I think that maybe only one wing will stall during the departure phase of the spin, by the time the spin is in the developed stage both wings will be stalled. I think the test question could have been better worded though.
$endgroup$
– DLH
39 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@DLH I think this is a poor answer because it is wrong.
$endgroup$
– Peter Kämpf
29 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
$begingroup$
@PeterKämpf: Oh man I wish you had answered sooner, I was persuaded.
$endgroup$
– DLH
20 mins ago
add a comment |
$begingroup$
A spin is an autorotation that requires an asymmetric thrust force to sustain. This requires the wing span to be anchored at one end by drag, with the other end developing enough thrust to overcome the (rather weak) stabilizing force of the vertical fin and drive that end forward, rotating the plane. The AOA is highest at the inboard end and decreases as you move outboard due to the higher forward velocity. At some point along the span, the outer end is unstalled or only semi-stalled and is making at least some amount of lift/thrust.
$endgroup$
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$begingroup$
A spin is an autorotation that requires an asymmetric thrust force to sustain. This requires the wing span to be anchored at one end by drag, with the other end developing enough thrust to overcome the (rather weak) stabilizing force of the vertical fin and drive that end forward, rotating the plane. The AOA is highest at the inboard end and decreases as you move outboard due to the higher forward velocity. At some point along the span, the outer end is unstalled or only semi-stalled and is making at least some amount of lift/thrust.
$endgroup$
add a comment |
$begingroup$
A spin is an autorotation that requires an asymmetric thrust force to sustain. This requires the wing span to be anchored at one end by drag, with the other end developing enough thrust to overcome the (rather weak) stabilizing force of the vertical fin and drive that end forward, rotating the plane. The AOA is highest at the inboard end and decreases as you move outboard due to the higher forward velocity. At some point along the span, the outer end is unstalled or only semi-stalled and is making at least some amount of lift/thrust.
$endgroup$
A spin is an autorotation that requires an asymmetric thrust force to sustain. This requires the wing span to be anchored at one end by drag, with the other end developing enough thrust to overcome the (rather weak) stabilizing force of the vertical fin and drive that end forward, rotating the plane. The AOA is highest at the inboard end and decreases as you move outboard due to the higher forward velocity. At some point along the span, the outer end is unstalled or only semi-stalled and is making at least some amount of lift/thrust.
answered 20 mins ago
John KJohn K
24.3k13674
24.3k13674
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