How to align text above triangle figure Announcing the arrival of Valued Associate #679: Cesar...

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How to align text above triangle figure



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizealign text in tikz figureNumerical conditional within tikz keys?Relating tree nodes in forest to content in a tableTikZ: Node position in draw environmentLatex and Game Theory: Combining an Extensive and Normal Form for a Three Players GameDrawing graph with Tikz: Link it with main text without overlapping with textTikZ: define arrow starting position based on style and format node label












1















I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



Is there a better way to get the same alignment that I have now without the excessive use of ~?



enter image description here



documentclass[hidelinks,14pt, letterpaper]{extarticle}
usepackage{amsmath, amssymb, tikz}

newcommand{pythagwidth}{3cm}
newcommand{pythagheight}{2cm}

begin{document}
begin{figure}[h]
centering

begin{tikzpicture}[scale=1.25]
coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
draw
(A) --
node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
node[right] {?} (C) --
node[below] {?}
(A);
draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

end{tikzpicture}
caption{Caption}
label{fig:my_label}
end{figure}
end{document}









share|improve this question



























    1















    I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



    Is there a better way to get the same alignment that I have now without the excessive use of ~?



    enter image description here



    documentclass[hidelinks,14pt, letterpaper]{extarticle}
    usepackage{amsmath, amssymb, tikz}

    newcommand{pythagwidth}{3cm}
    newcommand{pythagheight}{2cm}

    begin{document}
    begin{figure}[h]
    centering

    begin{tikzpicture}[scale=1.25]
    coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
    coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
    coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
    draw
    (A) --
    node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
    node[right] {?} (C) --
    node[below] {?}
    (A);
    draw
    (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

    end{tikzpicture}
    caption{Caption}
    label{fig:my_label}
    end{figure}
    end{document}









    share|improve this question

























      1












      1








      1








      I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



      Is there a better way to get the same alignment that I have now without the excessive use of ~?



      enter image description here



      documentclass[hidelinks,14pt, letterpaper]{extarticle}
      usepackage{amsmath, amssymb, tikz}

      newcommand{pythagwidth}{3cm}
      newcommand{pythagheight}{2cm}

      begin{document}
      begin{figure}[h]
      centering

      begin{tikzpicture}[scale=1.25]
      coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
      coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
      coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
      draw
      (A) --
      node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
      node[right] {?} (C) --
      node[below] {?}
      (A);
      draw
      (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

      end{tikzpicture}
      caption{Caption}
      label{fig:my_label}
      end{figure}
      end{document}









      share|improve this question














      I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



      Is there a better way to get the same alignment that I have now without the excessive use of ~?



      enter image description here



      documentclass[hidelinks,14pt, letterpaper]{extarticle}
      usepackage{amsmath, amssymb, tikz}

      newcommand{pythagwidth}{3cm}
      newcommand{pythagheight}{2cm}

      begin{document}
      begin{figure}[h]
      centering

      begin{tikzpicture}[scale=1.25]
      coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
      coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
      coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
      draw
      (A) --
      node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
      node[right] {?} (C) --
      node[below] {?}
      (A);
      draw
      (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

      end{tikzpicture}
      caption{Caption}
      label{fig:my_label}
      end{figure}
      end{document}






      tikz-pgf






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 1 hour ago









      Evan KimEvan Kim

      1453




      1453






















          2 Answers
          2






          active

          oldest

          votes


















          3














          Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



          documentclass[hidelinks,14pt, letterpaper]{extarticle}
          usepackage{amsmath, amssymb, tikz}

          newcommand{pythagwidth}{3cm}
          newcommand{pythagheight}{2cm}

          begin{document}
          begin{figure}[h]
          centering

          begin{tikzpicture}[scale=1.25]
          coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
          coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
          coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
          draw
          (A) --
          node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
          node[right] {?} (C) --
          node[below] {?}
          (A);
          draw
          (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

          end{tikzpicture}
          caption{Caption}
          label{fig:my_label}
          end{figure}
          end{document}


          enter image description here



          ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}[scale=1.25]
          draw (-1.5,-1) coordinate [label=left:$A$] (A) --
          node[midway,above,sloped] {$sqrt{1+x^2}$}
          (1.5,1) coordinate [label=above:$B$] (B) --
          node[right] {?}
          (1.5,-1)coordinate [label=below right:$C$] (C) --
          node[below] {?} cycle;
          draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago





















          1














          Just for fun: with pstricks, a very short code to have this figure:



           documentclass{article}
          usepackage{pst-eucl}%,
          usepackage{auto-pst-pdf}

          begin{document}

          begin{postscript}
          psset{unit=2, linejoin=1, PointSymbol=none,}
          pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
          ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
          psset{PointName=none}
          pstMiddleAB{A}{C}{I}uput[d](I){?}
          pstMiddleAB{B}{C}{J}uput[r](J){?}
          end{postscript}

          end{document}


          enter image description here






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago


















            3














            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago
















            3












            3








            3







            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer















            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 27 mins ago

























            answered 1 hour ago









            marmotmarmot

            118k6153288




            118k6153288













            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago





















            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago



















            yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago







            yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago













            1














            Just for fun: with pstricks, a very short code to have this figure:



             documentclass{article}
            usepackage{pst-eucl}%,
            usepackage{auto-pst-pdf}

            begin{document}

            begin{postscript}
            psset{unit=2, linejoin=1, PointSymbol=none,}
            pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
            ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
            psset{PointName=none}
            pstMiddleAB{A}{C}{I}uput[d](I){?}
            pstMiddleAB{B}{C}{J}uput[r](J){?}
            end{postscript}

            end{document}


            enter image description here






            share|improve this answer




























              1














              Just for fun: with pstricks, a very short code to have this figure:



               documentclass{article}
              usepackage{pst-eucl}%,
              usepackage{auto-pst-pdf}

              begin{document}

              begin{postscript}
              psset{unit=2, linejoin=1, PointSymbol=none,}
              pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
              ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
              psset{PointName=none}
              pstMiddleAB{A}{C}{I}uput[d](I){?}
              pstMiddleAB{B}{C}{J}uput[r](J){?}
              end{postscript}

              end{document}


              enter image description here






              share|improve this answer


























                1












                1








                1







                Just for fun: with pstricks, a very short code to have this figure:



                 documentclass{article}
                usepackage{pst-eucl}%,
                usepackage{auto-pst-pdf}

                begin{document}

                begin{postscript}
                psset{unit=2, linejoin=1, PointSymbol=none,}
                pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
                ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
                psset{PointName=none}
                pstMiddleAB{A}{C}{I}uput[d](I){?}
                pstMiddleAB{B}{C}{J}uput[r](J){?}
                end{postscript}

                end{document}


                enter image description here






                share|improve this answer













                Just for fun: with pstricks, a very short code to have this figure:



                 documentclass{article}
                usepackage{pst-eucl}%,
                usepackage{auto-pst-pdf}

                begin{document}

                begin{postscript}
                psset{unit=2, linejoin=1, PointSymbol=none,}
                pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
                ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
                psset{PointName=none}
                pstMiddleAB{A}{C}{I}uput[d](I){?}
                pstMiddleAB{B}{C}{J}uput[r](J){?}
                end{postscript}

                end{document}


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 47 mins ago









                BernardBernard

                176k778210




                176k778210






























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