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Why boldmath fails in a tikz node?

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6

0

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (0,0) node[draw]{boldmath (+)} (1,1);

end{tikzpicture}

end{document}

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.



See the tikz package documentation for explanation.

Type  H <return>  for immediate help.

 ...                                              



l.6     path (0,0) node[draw]{boldmath (+)}

                                                (1,1);

? 

If I double the braces in the node, as

path (0,0) node[draw]{{boldmath (+)}} (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 4 hours ago

RmanoRmano

8,33621649

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  boldmath is not deprecated.
  
  – David Carlisle
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  I seem to recall that tikz only allows a certain number of expansions while looking for the ; and the full definition of boldmath is rather complicated so perhaps it is too much....
  
  – David Carlisle
  3 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
  
  – Rmano
  4 mins ago
  

  
  
  
  

add a comment | 

6

0

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (0,0) node[draw]{boldmath (+)} (1,1);

end{tikzpicture}

end{document}

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.



See the tikz package documentation for explanation.

Type  H <return>  for immediate help.

 ...                                              



l.6     path (0,0) node[draw]{boldmath (+)}

                                                (1,1);

? 

If I double the braces in the node, as

path (0,0) node[draw]{{boldmath (+)}} (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 4 hours ago

RmanoRmano

8,33621649

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  boldmath is not deprecated.
  
  – David Carlisle
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  I seem to recall that tikz only allows a certain number of expansions while looking for the ; and the full definition of boldmath is rather complicated so perhaps it is too much....
  
  – David Carlisle
  3 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
  
  – Rmano
  4 mins ago
  

  
  
  
  

add a comment | 

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (0,0) node[draw]{boldmath (+)} (1,1);

end{tikzpicture}

end{document}

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.



See the tikz package documentation for explanation.

Type  H <return>  for immediate help.

 ...                                              



l.6     path (0,0) node[draw]{boldmath (+)}

                                                (1,1);

? 

If I double the braces in the node, as

path (0,0) node[draw]{{boldmath (+)}} (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 4 hours ago

RmanoRmano

8,33621649

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (0,0) node[draw]{boldmath (+)} (1,1);

end{tikzpicture}

end{document}

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.



See the tikz package documentation for explanation.

Type  H <return>  for immediate help.

 ...                                              



l.6     path (0,0) node[draw]{boldmath (+)}

                                                (1,1);

? 

path (0,0) node[draw]{{boldmath (+)}} (1,1);

share|improve this question

asked 4 hours ago

RmanoRmano

8,33621649

share|improve this question

asked 4 hours ago

RmanoRmano

8,33621649

asked 4 hours ago

RmanoRmano

8,33621649

asked 4 hours ago

RmanoRmano

8,33621649

1 Answer
1

active

oldest

votes

3

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (1,0) node[draw,font=boldmath]{ (+)};

    path (2,0) node[draw,node font=boldmath]{ (+)};

    path (3,0) node[draw]{ (+)};

end{tikzpicture}

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

121k6159297

add a comment | 

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3

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (1,0) node[draw,font=boldmath]{ (+)};

    path (2,0) node[draw,node font=boldmath]{ (+)};

    path (3,0) node[draw]{ (+)};

end{tikzpicture}

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

121k6159297

add a comment | 

3

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (1,0) node[draw,font=boldmath]{ (+)};

    path (2,0) node[draw,node font=boldmath]{ (+)};

    path (3,0) node[draw]{ (+)};

end{tikzpicture}

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

121k6159297

add a comment | 

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (1,0) node[draw,font=boldmath]{ (+)};

    path (2,0) node[draw,node font=boldmath]{ (+)};

    path (3,0) node[draw]{ (+)};

end{tikzpicture}

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

121k6159297

documentclass[border=10pt]{standalone}

usepackage{tikz}

begin{document}

begin{tikzpicture}

    path (1,0) node[draw,font=boldmath]{ (+)};

    path (2,0) node[draw,node font=boldmath]{ (+)};

    path (3,0) node[draw]{ (+)};

end{tikzpicture}

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

121k6159297

answered 2 hours ago

marmotmarmot

121k6159297

answered 2 hours ago

marmotmarmot

121k6159297